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Use the map type template parameter to access map()

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It is more natural than using the family subtype and also
use two single maps instead of a std::pair.

No functional change.

Signed-off-by: Marco Costalba <mcostalba@gmail.com>
This commit is contained in:
Marco Costalba
2011-09-11 10:45:59 +01:00
parent b706165527
commit 35018fa307
2 changed files with 22 additions and 28 deletions
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22
src/endgame.h
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@@ -98,20 +98,28 @@ private:
struct Endgames {
template<typename T>
struct EMap { typedef std::map<Key, EndgameBase<T>*> type; };
struct Map { typedef std::map<Key, EndgameBase<T>*> type; };
typedef Map<Value>::type M1;
typedef Map<ScaleFactor>::type M2;
Endgames();
~Endgames();
template<typename T> EndgameBase<T>* get(Key key) const;
template<typename T>
EndgameBase<T>* get(Key key) const {
typedef typename Map<T>::type M;
typename M::const_iterator it = map<M>().find(key);
return it != map<M>().end() ? it->second : NULL;
}
private:
template<EndgameType E> void add(const std::string& keyCode);
template<typename M> const M& map() const;
// Here we store two maps, for evaluate and scaling functions...
std::pair<EMap<Value>::type, EMap<ScaleFactor>::type> maps;
// ...and here is the accessing template function
template<typename T> const typename EMap<T>::type& map() const;
M1 m1;
M2 m2;
};
#endif // !defined(ENDGAME_H_INCLUDED)