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Remove xxx_of_color() helpers

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They hide the underlying uniform function call with
no benefit.

A little bit more verbose but now is clear what happens.

No functional change.

Signed-off-by: Marco Costalba <mcostalba@gmail.com>
This commit is contained in:
Marco Costalba
2009-02-17 10:54:47 +01:00
parent f32992f88c
commit 2c955f25de
6 changed files with 23 additions and 47 deletions
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12
src/position.h
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@@ -529,12 +529,12 @@ inline Square Position::initial_qr_square(Color c) const {
}
inline Bitboard Position::pawn_attacks(Color c, Square s) const {
return StepAttackBB[pawn_of_color(c)][s];
return StepAttackBB[piece_of_color_and_type(c, PAWN)][s];
}
template<>
inline Bitboard Position::piece_attacks<PAWN>(Square s) const {
return StepAttackBB[pawn_of_color(opposite_color(sideToMove))][s];
return StepAttackBB[piece_of_color_and_type(opposite_color(sideToMove), PAWN)][s];
}
template<>
@@ -675,28 +675,28 @@ inline Phase Position::game_phase() const {
inline bool Position::move_is_deep_pawn_push(Move m) const {
Color c = side_to_move();
return piece_on(move_from(m)) == pawn_of_color(c)
return piece_on(move_from(m)) == piece_of_color_and_type(c, PAWN)
&& relative_rank(c, move_to(m)) > RANK_4;
}
inline bool Position::move_is_pawn_push_to_7th(Move m) const {
Color c = side_to_move();
return piece_on(move_from(m)) == pawn_of_color(c)
return piece_on(move_from(m)) == piece_of_color_and_type(c, PAWN)
&& relative_rank(c, move_to(m)) == RANK_7;
}
inline bool Position::move_is_passed_pawn_push(Move m) const {
Color c = side_to_move();
return piece_on(move_from(m)) == pawn_of_color(c)
return piece_on(move_from(m)) == piece_of_color_and_type(c, PAWN)
&& pawn_is_passed(c, move_to(m));
}
inline bool Position::move_was_passed_pawn_push(Move m) const {
Color c = opposite_color(side_to_move());
return piece_on(move_to(m)) == pawn_of_color(c)
return piece_on(move_to(m)) == piece_of_color_and_type(c, PAWN)
&& pawn_is_passed(c, move_to(m));
}