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Reuse 5 slots instead of 4

Browse Source 
But this time with the guarantee of an always aligned
access so that prefetching is not adversely impacted.

On Joona PC
1+0, 64Mb hash:

Orig - Mod: 174 - 237 - 359

Instead after 1000 games at 1+0 with 128MB hash size
we are at + 1 ELO (just 4 games of difference).

Signed-off-by: Marco Costalba <mcostalba@gmail.com>
This commit is contained in:
Marco Costalba
2009-08-11 08:30:19 +01:00
parent 8d369600ec
commit 166c09a7a0
2 changed files with 21 additions and 11 deletions
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11
src/tt.cpp
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@@ -33,9 +33,6 @@
#include <xmmintrin.h>
#endif
// This is the number of TTEntry slots for each position
static const int ClusterSize = 4;
// The main transposition table
TranspositionTable TT;
@@ -67,14 +64,14 @@ void TranspositionTable::set_size(unsigned mbSize) {
// We store a cluster of ClusterSize number of TTEntry for each position
// and newSize is the maximum number of storable positions.
while ((2 * newSize) * ClusterSize * (sizeof(TTEntry)) <= (mbSize << 20))
while ((2 * newSize) * sizeof(TTCluster) <= (mbSize << 20))
newSize *= 2;
if (newSize != size)
{
size = newSize;
delete [] entries;
entries = new TTEntry[size * ClusterSize];
entries = new TTCluster[size];
if (!entries)
{
std::cerr << "Failed to allocate " << mbSize
@@ -93,7 +90,7 @@ void TranspositionTable::set_size(unsigned mbSize) {
void TranspositionTable::clear() {
memset(entries, 0, size * ClusterSize * sizeof(TTEntry));
memset(entries, 0, size * sizeof(TTCluster));
}
@@ -103,7 +100,7 @@ void TranspositionTable::clear() {
inline TTEntry* TranspositionTable::first_entry(const Key posKey) const {
return entries + ((uint32_t(posKey) & (size - 1)) * ClusterSize);
return entries[uint32_t(posKey) & (size - 1)].data;
}